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4.9x^2+5x-1.4=0
a = 4.9; b = 5; c = -1.4;
Δ = b2-4ac
Δ = 52-4·4.9·(-1.4)
Δ = 52.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{52.44}}{2*4.9}=\frac{-5-\sqrt{52.44}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{52.44}}{2*4.9}=\frac{-5+\sqrt{52.44}}{9.8} $
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